Skip to main content

12

Q1. Show that the points (-2, 3 , 5 ) , ( 1, 2 , 3 ) and ( 7, 0 , -1 ) are collinear.

Solution

Q2. Find the co-ordinates of the point which divide the line segment joining the point (1,-2,3) and (3,4,-5) in the ratio 2 : 3 externally.

Solution

Q3. Find the ratio in which the line segment joining the points (5,9,11) and (7,11,-9) is divided by the YZ plane

Solution

Q4. Name the octant in which the following points lie : (i) (4,-2,-5) (ii) (-4,2,-5)(iii) (1,2,3)

Solution

(i) VIIIth Octant (ii) VIth Octant (iii) Ist Octant
Q5. A point is in the YZ plane. What is the value of the x-coordinate?

Solution

Since the point lies in the YZ plane the value of x-cordinate is zero.
Q6. Find the equation of the set of points which are equidistant from the points (1, 2, 3) and (3, 2, -1)

Solution

Q7. If the origin is the centroid of the triangle PQR with vertices P(2a,2,6) Q(-4,3b,-10) and R(8,14,2c), then find the values of a,b,c

Solution

Q8. The centroid of a triangle ABC is at the point (1,1,1). If the coordinates of A and B are (4,-6,4) and (-2,8,-7)respectively, find the coordinates of the point C.

Solution

Q9. F i n d space t h e space c o minus o r d i n a t e s space o f space a space p o i n t space o n space t h e space y minus a x i s space a t space a space d i s tan c e space 5 square root of 2 space f r o m
t h e space p o i n t space A left parenthesis 3 comma 2 comma 5 right parenthesis

Solution

A n y space p o i n t space o n space y space a x i s space i s space g i v e n space b y space left parenthesis 0 comma y comma 0 right parenthesis
D i s tan c e space o f space t h i s space p o i n t space f r o m space left parenthesis 3 comma 2 comma 5 right parenthesis space i s space 5 square root of 2
rightwards double arrow left parenthesis 0 minus 3 right parenthesis squared plus left parenthesis y minus 2 right parenthesis squared plus left parenthesis 0 minus 5 right parenthesis squared equals 50
rightwards double arrow y squared minus 4 y minus 12 equals 0
rightwards double arrow y equals 6 comma negative 2
S o space t h e space c o minus o r d i n a t e s space a r e space left parenthesis 0 comma 6 comma 0 right parenthesis space a n d space left parenthesis 0 comma negative 2 comma 0 right parenthesis
Q10. A point P is at a distance of 6 units from the origin on the Z axis. Write the coordinates of P

Solution

The coordinates of P are left parenthesis 0 comma 0 comma plus-or-minus 6 right parenthesis
Q11. Find the distance between the points P(1, -3, 4) and Q (- 4, 1, 2).

Solution



Comments

Popular posts from this blog

10

Q1. 1) 780 2) 861 3) 820 4) 901 Solution Q2. Solution Let the given points be D(p, 0), E(r, s) and F(0, q) Since the points lie on the same line,  Slope of DE = Slope of EF                Slope of DE =  Slope of EF =  Q3. Without using distance formula, show that the points (-2, 1), (5, 3), (6, 7) and (- 4, 5) are not the vertices of a parallelogram. Solution Q4. Find the slope of line which passes through the point (5, 6) and the mid-point of line joining the points (4, 6) and (-3, 7). Solution Mid-point joining the line segment the points (4, 6) and (-3, 7) = Slope of line joining the points (5, 6) and Q5. If three points (3, 6), (-5, 7) and (x, 1) are collinear, find the value of x. Solution ...

15

Q1. Solution Q2. Solution         Class interval x f xf d=|x-mean| fd 0-10 5 5 25 22 110 10-20 15 8 120 12 96 20-30 25 15 375 2 30 30-40 35 16 560 8 128 40-50 45 6 270 18 108 total   50 1350   472 Class interval x f cf d=|x-median| fd 0-10 5 5 5 20 100 10-20 15 8 13 5 40 20-30 25 15 28 0 0 30-40 35 16 44 10 160 40-50 45 6 50 20 120 total   50     420 Q3. Solution Q4. Solution Q5. Solution Q6. Solution Q7. Solution Firm B shows greater variability. Q8. Solution Q9. Solution Q10. Solution Q11. Solution Q12. Solution Take Another Test