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Q1. How many liters of water will have to be added to 1125 liters of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content?

Solution

Let us assume that l liters of water is added to 1125 liters so that the resulting mixture contain more than 25% but less than 30% acid solution. Lets first calculate the acid content in 1125 liters (45% acid). i.e., liters Now when l liter of solution is added so the volume becomes (1125 + l) liter.   Now according to question the acid content should be more than 25% but less than 30% so   Now this can be written as two inequalities,  and Multiplying by 100 25 l less than fraction numerator 1125 cross times 20 over denominator blank end fraction
l less than fraction numerator 1125 cross times 20 over denominator 25 end fraction
l less than 900
Solving 2nd inequality then     Hence the quantity of water added should be greater than 562.5 litre but less than 900.
Q2. Find the integral values of two numbers such that their sum is 11 and the product is greater than 28.

Solution

Let the numbers be x & y                          4< x < 7 Integral values of x=5,6 Hence corresponding value of y= 6,5 So the solution is x=5, y=6 or x=6, y=5       
Q3. Find the solution for the pair of inequalities x +5 >2x-9  and 2x-11>4(x-1).

Solution

x +5 > 2x-9,        2x-11 > 4(x-1)     -x > -14,          2x-11 > 4x - 4      x < 14,              -2x  > 7                                   x < fraction numerator negative 7 over denominator 2 end fraction                               -3.5 > x       Clearly, from the graph the solution is x < -3.5
Q4. In a game, a person wins if he gets the sum greater than 20 in four throws of a die. In three throws he got numbers 6, 5, 4. What should be his fourth throw, so that he wins the game?

Solution

Numbers obtained in three throws are 6, 5 and 4. Let the number obtained in fourth throw be x. Now, Sum > 20     6 + 5 + 4 + x > 20     15 + x > 20     x > 20 – 15     x > 5   He must get a 6 in the fourth throw to win the game.
Q5. Find all pairs of consecutive odd positive integers, both of which are greater than 15, such that their sum is less than 50.

Solution

Let the pair of consecutive odd positive integers be x, x + 2 such that both are greater than 15 and their sum is less than 50     x > 15 and  x + (x + 2) < 50     x > 15 and  2x + 2 < 50     x > 15 and  2x < 48     x > 15 and  x < 24     15 < x < 24 and x is odd     x = 17, 19, 21, 23 and therefore, x + 2 = 19, 21, 23, 25     Possible pairs are (17, 19), (19, 21), (21, 23), (23, 25)
Q6. Solve the inequality and represent the solution graphically on the number line.

Solution

or or
Q7. Show that the solution set is empty for the system of inequations:     2x-y less or equal than1, 4x-2y-9greater or equal than0

Solution

The graphs for the lines 2x - y = 1 and 4x -2 y =9 are                                 The region shaded in green represents the inequality 2x - y less or equal than 1 and the orange shaded region represents 4x -2y greater or equal than 9. Clearly there is no common portion of both the regions. Hence the solution set of the given system is empty.
Q8. A company manufactures cassettes and its cost equation for a week is C = 300 + 1.5x and its revenue equation is R = 2x, where x is the number of cassettes sold in a week. How many cassettes must be sold for the company to realize a profit?

Solution

For profit: Revenue > Cost     2x > 300 + 1.5x     2x – 1.5x > 300     (0.5)x > 300         x > 600    Number of cassettes sold > 600
Q9. Show that the solution set is empty for the system of inequalities                    2x + y &gege; 4 and 2x + y < -6

Solution

We draw the graphs for the lines 2x + y = 4 and 2x + y = -6                     Now you can see that the region shaded in red represents the inequality 2x + y ≥ 4 and that in green represents 2x + y < -6 clearly there is no portion of both the regions in common and hence the solution set of given system is empty.    
Q10. Find the area enclosed by the system of inequalities            

Solution

The required region will be given by the rectangle ABCD and hence the area enclosed is 2 sq. units                
Q11. Find the vertices of the figure enclosing the region represented by the following system of inequalities.                                                                                                                                              7x + 10y less or equal than 70                    3x + y less or equal than 18                    x greater or equal than 0, y greater or equal than 1.

Solution

We first draw the graphs of the linear equations 7x + 10y = 70, 3x + y = 18 and y = 1.     The region which represents the inequality 7x + 10y 70 is containing the origin. The region which represents the inequality 3x + y  18 is also containing the origin. The region which represents the inequality y  1 is the region away from origin i.e on the right side of line y = 1 and of course x  0 is the region on the right side of y axis.   Hence the common region is given by ABCD and the vertices are A (0, 1), B(0, 7) C, D  
Q12. IQ of a person is given by the formula , where M A is mental age and CA is chronological age. If  for a group of 15-year children, find the range of their mental age.

Solution

Given,         15 less or equal than M A less or equal than 24   Range of mental age is 15 to 24
Q13. The water acidity in a pool is considered normal when the average pH reading of three daily measurements is between 9.2 and 9.8. If first two pH readings are 9.48 and 9.85, find the range of pH value for the third reading that will result in the acidity level being normal.

Solution

Let the third reading be x       27.6 < 19.33 + x < 29.4     27.6 – 19.33 < x < 29.4 - 19.33     8.27 < x < 10.07    Range of pH value for third reading is 8.27 to 10.07


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