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3

Q1.

Solution

a equals 9 comma space b equals 10 comma space c equals 6
cos left parenthesis A right parenthesis equals fraction numerator b squared plus c squared minus a squared over denominator 2 b c end fraction equals fraction numerator 100 plus 36 minus 81 over denominator 2 x 10 x 6 end fraction equals 11 over 24
cos left parenthesis B right parenthesis equals fraction numerator a squared plus c squared minus b squared over denominator 2 a c end fraction equals fraction numerator 81 plus 36 minus 100 over denominator 2 x 9 x 6 end fraction equals 17 over 108
cos left parenthesis C right parenthesis equals fraction numerator a squared plus b squared minus c squared over denominator 2 a b end fraction equals fraction numerator 81 plus 100 minus 36 over denominator 2 x 9 x 10 end fraction equals 29 over 36
Q2.

Solution

Q3. =

Solution

L.H.S.= +             =              =               =               =  
Q4. What is the value of

Solution

    (1).(-1)(1)…………..51terms. So in the whole series there are 26 terms which is 1 and 25 terms (-1) So product of 25 (-1)s  is (-1) Hence, is -1.
Q5.

Solution

Q6. Calculate cos15o

Solution

cos15o = cos(45o – 30o)              = cos45ocos30o + sin45o sin30o                          
Q7.

Solution

Q8. If  find the value of

Solution

Using tan(x+y) we have =, === Substituting the values we get, ==2
Q9.

Solution

Q10. Prove that, =

Solution

L.H.S.= dividing the expression by = = = = = =R.H.S. Hence proved.
Q11. Prove that,

Solution

L.H.S.= = = =   Hence proved.
Q12. Prove that,

Solution

L.H.S.= = =[ using the property  and ] = =R.H.S. H ence proved.
Q13.  Convert 22.22c into degree measure.

Solution

We know that    1=    So degree measure =   Radian   Degree measure = =     hence
Q14.

Solution

Q15. Prove that,Cos (A + B). cos (A - B) = cos2 A - sin2 B

Solution

Q16.

Solution

Q17. Solve

Solution

 either  or  either  or  either  or  as both cases together give all multiples of we have  where n is an integer.  
Q18. Evaluate:

Solution

 
Q19. Prove that,

Solution

Q20.

Solution

Q21. Prove that, =

Solution

LHS=  =          =            = = =      =RHS
Q22. Prove that,

Solution

L.H.S.= = = = = = = = =R.H.S.
Q23. Prove that, =

Solution

L.H.S.=            =            =            =
Q24. Prove that,

Solution

L.H.S. =            =            = =   =RHS
Q25.

Solution

Q26. Given 2A,2B,2C are angles of a triangle, Prove that

Solution

so = so cross multiplying we get Hence proved.  
Q27. Draw the graph of y = cos2x,

Solution

         So, the graph of above function is as follows-
Q28. A n space a i r c r a f t space t r a c k i n g space s t a t i o n space d e t e r m i n e s space t h e space d i s tan c e space f r o m space a space c o m m o n space p o i n t space O
t o space e a c h space a i r c r a f t space a n d space t h e space a n g l e space b e t w e e n space t h e space a i r c r a f t s. I f space a n g l e space O space b e t w e e n space t h e space t w o space a i r c r a f t s space i s space 49 to the power of 0
a n d space t h e space d i s tan c e space f r o m space p o i n t space O space t o space t h e space t w o space a i r c r a f t s space a r e space 50 k m space a n d space 72 k m comma f i n d space t h e space d i s tan c e space b e t w e e n space t h e space t w o space a i r c r a f t s ?

Solution

Q29. Prove that,sin 50o - sin 70o + sin 10o = 0

Solution

Q30. Draw the graph of y =

Solution

To draw the graph, we shall first find the values of x in the interval [0, ]. We know that, Hence the graph of the given function is as follows-  
Q31. Solve

Solution

     either  or  either  or   either   or  either       where n, m are integers.
Q32.

Solution

Q33.

Solution

Hence the value of 
Q34.

Solution

Q35. Solve

Solution

 dividing the equation by 2 through out, we get sin left parenthesis theta plus pi divided by 6 right parenthesis    where n is an integer
Q36.   Convert  into radian measure.

Solution

As     Therefore   =   1o =  radians  =  radian = radian=Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.
Q37.

Solution

Q38.

Solution

Q39. Evaluate sin105o + cos105o.

Solution

sin105o + cos105o = sin (60o + 45o) + cos (60o + 45o)  = sin60o cos45o + cos60o sin45o + cos60o cos45o - sin60o sin45o    
Q40.

Solution

Q41. Find the angle between the minute hand and the hour hand of a clock when the time is 5:20.

Solution

In 12 hours hour hand moves by 360 degrees In 1 hr it will move by 30 degrees So in 1 min it will move ½ degree So in 5 hr and 20 min it will move 5 x 30 + 20 x ½ = 160 degree For minute hand In 60 min it moves 360 degree So in 1 min it moves 6 degree. So in 20 min it moves 20x6 =120 degree. Therefore difference is 160 – 120 = 40 degree
Q42. =

Solution

L.H.S.= = = = = = = = =R.H.S. Hence proved.
Q43. If , show that

Solution

squaring both sides hence proved
Q44. What is the value of the supplementary angle to the sum of .

Solution

S u m space o f space t w o space a n g l e s equals 44 degree 45 apostrophe 46 apostrophe apostrophe plus 46 degree 45 apostrophe 44 apostrophe apostrophe equals 90 degree 90 apostrophe 90 apostrophe apostrophe
W e space k n o w space t h a t space 60 apostrophe equals 1 degree space a n d space 60 apostrophe apostrophe equals 1 apostrophe
H e n c e comma space
90 degree 90 apostrophe 90 apostrophe apostrophe equals 90 degree 60 apostrophe 90 apostrophe apostrophe plus 30 apostrophe
space space space space space space space space space space space space space space space space space space space equals 90 degree 1 degree 60 apostrophe apostrophe plus 30 apostrophe space plus 30 apostrophe apostrophe
space space space space space space space space space space space space space space space space space space space equals 91 degree 1 apostrophe plus 30 apostrophe space plus 30 apostrophe apostrophe space space
space space space space space space space space space space space space space space space space space space space equals 91 degree 31 apostrophe 30 apostrophe apostrophe space
T h e r e f o r e space t h e space s u p p l e m e n t a r y space a n g l e space i s space 180 degree minus 91 degree 31 apostrophe 30 apostrophe apostrophe
space 180 degree minus 91 degree 31 apostrophe 30 apostrophe apostrophe equals 179 degree 59 apostrophe 60 apostrophe apostrophe minus 91 degree 31 apostrophe 30 apostrophe apostrophe
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 88 degree 28 apostrophe 30 apostrophe apostrophe
H e n c e space t h e space s u p p l e m e n t a r y space a n g l e space i s space 88 degree 28 apostrophe 30 apostrophe apostrophe
Q45. Solve

Solution

either  or  either  or   either   or  or  where n, m are integers.
Q46.

Solution

Q47. Prove that, =

Solution

L.H.S. = =+ = = = R.H.S. Hence proved.
Q48. Solve

Solution

 either  or  either Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. or  either  or  where n,m are integers
Q49.

Solution

= = = = = = =R.H.S. Hence proved.  
Q50. The speed of sound is nearly 341m/s, if a car of wheel radius 70 cm moves with a speed of sound. Find the number of revolutions it will make in 10 sec.

Solution

Let n be the number of revolution a wheel makes in 10 sec.   The distance travelled by the wheel  in 10 sec is 3410 m   Therefore, n x  = 3410     rightwards double arrow n equals fraction numerator 3410 over denominator 2 πr end fraction equals fraction numerator 3410 cross times 7 over denominator 2 cross times 22 cross times 0.7 end fraction equals 775 space r e v o l u t i o n s
Q51. Draw the graph of y = tanx

Solution

We know that the value of tanx repeats after an interval of . To draw the graph we shall first find the values of tanx for some convenient values of x in [0, ]        W h e n space x equals 0 degree comma space y equals tan 0 degree equals 0
W h e n space x equals 30 degree comma space y equals t a n 30 degree equals fraction numerator 1 over denominator square root of 3 end fraction equals 0.58
W h e n space x equals 45 degree comma space y equals t a n 45 degree equals 1
W h e n space x equals 60 degree comma space y equals t a n 60 degree equals square root of 3 equals 1.732
W h e n space x equals 90 degree comma space y equals t a n 90 degree semicolon space y space i s space u n d e f i n e d
W h e n space x equals 120 degree comma space y equals t a n 120 degree equals negative square root of 3 equals negative 1.732
W h e n space x equals 135 degree comma space y equals t a n 135 degree equals negative 1
W h e n space x equals 150 degree comma space y equals t a n 150 degree equals negative fraction numerator 1 over denominator square root of 3 end fraction equals negative 0.58
W h e n space x equals 180 degree comma space y equals t a n 180 degree equals 0
We know that tan90o is not defined, but as the angle x approaches 90o from left side the value of tanx increases indefinitely. Similarly as the angle x approaches 90o from right side, the value of tanx decreases indefinitely. Hence the graph of above function is as follows-
Q52. Prove that, =

Solution

L.H.S. = =  =  = R.H.S. Hence proved.
Q53. P r o v e space t h a t space cos squared x plus cos squared left parenthesis x plus straight pi over 3 right parenthesis plus cos squared left parenthesis x minus straight pi over 3 right parenthesis equals 3 over 2

Solution

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