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Q1. Two finite sets have m and n elements. The total number of subsets of the first set is 112 more than the total number of subsets of the second set. Find the values of m and n.

Solution

                G i v e n :
space space space space space 2 to the power of m minus 2 to the power of n equals 112

rightwards double arrow 2 to the power of n open parentheses 2 to the power of m minus n end exponent minus 1 close parentheses equals 112

rightwards double arrow 2 to the power of n open parentheses 2 to the power of m minus n end exponent minus 1 close parentheses equals 2 to the power of 4 cross times 7 equals 2 to the power of 4 open parentheses 2 cubed minus 1 close parentheses

rightwards double arrow n equals 4 space a n d space m minus n equals 3

rightwards double arrow m equals 7
Q2. If A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, write a subset B of A that contain all multiples of 3.

Solution

B = {3, 6, 9}
Q3. Are the sets A - B and B - A  disjoint sets?

Solution

 A minus B space a A n d space B minus A space a r e space d i s j o i n t space s e t s.

A minus B equals open curly brackets x : x element of A space a n d space x not an element of B close curly brackets space a n d space B minus A equals open curly brackets x : x element of B space a n d space x not an element of A close curly brackets

rightwards double arrow open parentheses A minus B close parentheses intersection open parentheses B minus A close parentheses equals empty set  
Q4. If A = {2, 4, 6, 8}, B = {1, 3, 5, 6}, C = {5, 6, 7, 8, 9}. Verify that (A  B)  C = A (B  C)

Solution

A  B = {1, 2, 3, 4, 5, 6, 8} L.H.S. =  (A B) C            = {1, 2, 3, 4, 5, 6, 8}{ 5, 6, 7, 8, 9}           = {1, 2, 3, 4, 5, 6, 7, 8, 9} B  C   =   {1, 3, 5, 6, 7, 8, 9} R.H.S.  = A (B  C)             ={ 2, 4, 6, 8}{1, 3, 5, 6, 7, 8, 9}             = {1, 2, 3, 4, 5, 6, 7, 8, 9} Hence, L.H.S = R.H.S.
Q5. From the following Venn diagram determine A B.

Solution

A  B = {e, f}
Q6. If A = {2, 3, 4, 6}, B = {3, 5, 8}, C = {1, 3, 5, 8, 10}, then find (B – C) – (C – A):

Solution

B – C = , C – A = {1, 5, 8, 10} (B – C) – (C- A) =
Q7. Write the set {x : x  R, -4  x  4} as intervals.

Solution

The set in which end points are included is written using square bracket. So the given set in interval form can be written as [-4, 4]
Q8. Are the pair of sets A = {x : 3 < x < 4, x  Q} and B = { x : 3 < x < 4, x  N} Disjoint?

Solution

Here, A is the set of all rational numbers between 3 and 4. B is the set which does not contain any element. Hence, A  B = empty set. So, A and B are disjoint sets.
Q9. Is the collection of all even numbers between 7 and 19 a set?

Solution

Given collection is a set as it is well-defined and it contains the elements 8, 10, 12, 14, 16 and 18.
Q10. Write the set of all integers ‘x’ such that  open vertical bar x minus 4 close vertical bar less than 7 in roster form.

Solution

C a s e 1 colon space x greater or equal than 4

x minus 4 less than 7 rightwards double arrow x less than 11 space... space left parenthesis i right parenthesis

C a s e 2 colon x less than 4

minus open parentheses x minus 4 close parentheses less than 7 rightwards double arrow x greater than negative 3 space... space left parenthesis i i right parenthesis

F r o m space left parenthesis i right parenthesis space a n d space left parenthesis i i right parenthesis comma space w e space g e t
x equals open curly brackets negative 2 comma space minus 1 comma space 0 comma space 1 comma space 2 comma space 3 comma space 4 comma space 5 space comma 6 comma space 7 comma space 8 comma space 9 comma space 10 space close curly brackets
Q11. List all the elements of the set A = {x : x is a natural numbers, 2x + 4 < 25}

Solution

2x + 4 < 25   2x < 21             x < 10.5 Hence, A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Q12. How many elements has P(A), if A = {1}.

Solution

n open square brackets P open parentheses A close parentheses close square brackets equals 2 to the power of 1 equals 2
Q13. In a group, students know at least one of the languages, German or French. 100 students know German and 40 know French and 10 know both German and French. If there are 20 students who know neither of the two languages, how many students are there in the group?

Solution

Let G be the set of students who know German and F be the set of students who know French. So, we have     n(G  F) = n(G) + n(F) – n(G  F)  n(G  F) = 100 + 40 – 10 = 130 20 students who know neither of the two languages So, total students = 130 + 20 = 150
Q14. A survey was conducted on 110 people of Delhi. It was found that 65 people watched Hindi movie and 51 watched English movie and where as 24 watched both the movies. Find the number of people who did not watch any movie on that day.

Solution

Let A be the set of people who watched Hindi movie and B be the set of people who watched English movie.   G i v e n : space n open parentheses A close parentheses space equals space 65 comma space n open parentheses B close parentheses space equals space 51 space a n d space n open parentheses A intersection B close parentheses n open parentheses A union B close parentheses space equals space n open parentheses A close parentheses plus n open parentheses B close parentheses minus n open parentheses A intersection B close parentheses

space space space space space space space space space space space space space space space equals space 65 space plus space 51 space minus 24

space space space space space space space space space space space space space space space equals space 92          Thus the number of the people who watched either of the movie = 92 So, the number of people who did not watch any movie = 110 – 92 = 18.
Q15. From the following Venn diagram determine A  B.

Solution

A  B = {1, 2, 3, 6, 8}
Q16. Out of 600 mobile owners investigated, 500 owned Nokia hand set and 180 owned Tata hand set; 30 owned both Nokia and Tata hand sets. Is this data correct?

Solution

Let U denote the universal set consisting of all mobile owners, N denote the set of all owners of Nokia hand set and T denote the set of all owners of Tata hand- set. n(U) = 600, n(N) = 500, n(T) = 180, n(N  T) = 30. So, we have n (N T)   = n(N) + n(T) – n(N  T)                    = 500 + 180 – 30 = 650 Also, N  T is a subset of U.       But  n (N  T)  n(U)        650  600, which is impossible.        Given data is incorrect.
Q17. Is the following statement true? [3, 8]  (2, 10)

Solution

[3,8] = { x : 3  8, x  R} and (2, 10) = {x : 2 < x < 10, x  R}    [3, 8]  (2, 10) So the statement is true.
Q18. If A and B are two sets such that  A union B  has 40 elements, A has 30 elements and B has 20 elements, how many elements does the shaded region have?

Solution

                                                                         Here, the shaded region represents the intersection of two sets A and B. So, we have n open parentheses A union B close parentheses space equals space n open parentheses A close parentheses plus n open parentheses B close parentheses minus n open parentheses A intersection B close parentheses

rightwards double arrow 40 space equals space 30 plus 20 minus n open parentheses A intersection B close parentheses

rightwards double arrow n open parentheses A intersection B close parentheses space equals space 10                
Q19. Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A = {2, 3, 4} is a subset of B = {1, 2, 3, 4, 5}. Verify that  is a subset of .

Solution

U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} and A = {2, 3, 4} which is a subset of B = {1, 2, 3, 4, 5}.  = {6, 7, 8, 9, 10} and   = {1, 5, 6, 7, 8, 9, 10} Here, we observe that  is a subset of .
Q20. If A = {1, 2, 3, 4, 5}, B = {1, 3, 5, 8}, C = {2, 5, 7, 8}, verify that A – (B  C) = (A – B)  (A – C). 

Solution

B  C = {1, 2, 3, 5, 7, 8} L.H.S. = A – (B  C)             = {4} Now, A – B = {2, 4}, A – C = {1, 3, 4} R.H.S. = (A – B)  (A – C)            = {2, 4}  {1, 3, 4}            = {4}
Q21. Write the set {x : x is a month of a year not having 30 days} in roster form:

Solution

{January, February, March, May, July, August, October, December}
Q22. Are A = {x : x – 5 = 0} and B = {x : x is a positive  integral root of the equation x2 - 2x - 15} equal sets?

Solution

G i v e n space t h a t space A equals open curly brackets x colon x minus 5 equals 0 close curly brackets
T h u s comma space A equals open curly brackets 5 close curly brackets
C o n s i d e r space t h e space s e t space B equals open curly brackets x colon x space i s space a space p o s i t i v e space space i n t e g r a l space r o o t space o f space t h e space e q u a t i o n space x squared minus 2 x minus 15 close curly brackets
F a c t o r i z i n g space t h e space g i v e n space e q u a t i o n comma space w e space h a v e comma
x squared minus 2 x minus 15 equals 0
rightwards double arrow x squared minus 5 x plus 3 x minus 15 equals 0
rightwards double arrow x open parentheses x minus 5 close parentheses plus 3 open parentheses x minus 5 close parentheses equals 0
rightwards double arrow open parentheses x plus 3 close parentheses open parentheses x minus 5 close parentheses equals 0
rightwards double arrow x equals negative 3 space o r space x equals 5
S i n c e space x equals negative 3 space i s space n o t space a space p o s i t i v e space i n t e g r a l space r o o t comma space w e space h a v e comma space B equals open curly brackets 5 close curly brackets
T h u s comma space A equals B
Q23. I f space A equals open curly brackets 2 x : x element of N close curly brackets comma space B equals open curly brackets 3 x : x element of N close curly brackets comma space C equals open curly brackets 4 x : x element of N close curly brackets comma space t h e n space f i n d space open parentheses A intersection B close parentheses intersection C.

Solution

Here, A = {2, 4, 6, 8, 10, 12, ---}          B = {3, 6, 9, 12, ---}          C = {4, 8, 12, 16, ---} Now, A  B = {6, 12, ---} (A  B)  C = {6, 12, ---} {4, 8, 12, 16, ---}                       = {12, 24, ---} i.e.  (A  B) C = {12x : x  N}
Q24. In a group of 85 people, 50 like Hindi movies, 10 like both Hindi and English movies. How many like English movies and not Hindi. How many like English movies?

Solution

Let H denote the set of people who like Hindi movies and E be the set of people who like English movies, then n(H  E) = 85, n(H) = 50, n(H  E) = 10 We know that, n(H E) = n(H) + n(E) – n(H E)  85      = 50 + n(E) – 10  n(E)   =  45 No. of people who like English movies and not Hindi = n(E – H) Also, n(E) = n(E – H) + n(E H)  n(E – H) = 45 – 10 = 35


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